Multiplication•Grade 5•Missing Number

Grade 5 Multiplication Missing Number

Grade 5 multiplication missing number sheet: 24 problems on three-digit by two-digit multiplication.

CCSSAligned to Common Core 5.NBT.5: Fluently multiply multi-digit whole numbers using the standard algorithm.

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Three different problem sets — same skill, same layout, fresh numbers.

Preview — Set A

Find the number that belongs in each blank.

1.
859 × 35 = ___
2.
965 × ___ = 17370
3.
___ × 81 = 35316
4.
934 × 52 = ___
5.
720 × 62 = ___
6.
___ × 43 = 39818
7.
346 × ___ = 33562
8.
739 × 98 = ___
9.
152 × ___ = 10032
10.
___ × 56 = 17584
11.
303 × 32 = ___
12.
791 × ___ = 44296
13.
472 × ___ = 42008
14.
438 × 57 = ___
15.
257 × 63 = ___
16.
830 × 26 = ___
17.
147 × ___ = 8673
18.
___ × 62 = 15252
19.
981 × 74 = ___
20.
881 × 25 = ___
21.
612 × ___ = 44676
22.
956 × ___ = 19120
23.
522 × 72 = ___
24.
369 × 40 = ___

Other ways to solve this

Using 859 × 35 from this sheet (Set A, problem 1). Each method below reaches the same answer, 30,065, by a different route; pick the one that makes the most sense to you.

Partial products

Helps you see every piece of a long multiplication before adding them up.

859

× 35

455 × 9

2505 × 50

4,0005 × 800

27030 × 9

1,50030 × 50

24,00030 × 800

30,065

Step 1Split 859 into 800 + 50 + 9 and 35 into 30 + 5.
Step 2Multiply each part of 35 by each part of 859, starting with the ones.
- 5 × 9 = 45
- 5 × 50 = 250
- 5 × 800 = 4,000
- 30 × 9 = 270
- 30 × 50 = 1,500
- 30 × 800 = 24,000
Step 3Add the partial products: 45 + 250 + 4,000 + 270 + 1,500 + 24,000 = 30,065.
Step 4So 859 × 35 = 30,065.

Step 1 of 4

Lattice method

Helps keep carrying tidy: every digit product gets its own box, and you only add at the end.

Step 1Write 859 across the top and 35 down the right side, one digit per box.
Step 2Multiply each pair of digits. Put the tens above the diagonal and the ones below it.
- 3 × 8 = 24 → tens 2, ones 4
- 3 × 5 = 15 → tens 1, ones 5
- 3 × 9 = 27 → tens 2, ones 7
- 5 × 8 = 40 → tens 4, ones 0
- 5 × 5 = 25 → tens 2, ones 5
- 5 × 9 = 45 → tens 4, ones 5
Step 3Add along each diagonal, starting at the bottom right. Carry when a sum is 10 or more.
- Diagonal 1 (from the bottom right): 5 = 5
- Diagonal 2 (from the bottom right): 16 = 16: write 6, carry 1
- Diagonal 3 (from the bottom right): 9 + carry 1 = 10: write 0, carry 1
- Diagonal 4 (from the bottom right): 9 + carry 1 = 10: write 0, carry 1
- Diagonal 5 (from the bottom right): 2 + carry 1 = 3
Step 4Read the digits down the left side and along the bottom: 3 0 0 6 5. So 859 × 35 = 30,065.

Step 1 of 4

Doubling and halving

Helps when you can halve and double quickly: the only hard step is one addition at the end.

Halving the left column and doubling the right. Rows with an even left value are crossed out.
Halve	Double	Keep?
35	859	keep
17	1,718	keep
8	3,436	cross out
4	6,872	cross out
2	13,744	cross out
1	27,488	keep

Step 1Put the smaller number, 35, in the left column and 859 in the right column.
Step 2Halve the left number (drop any remainder) and double the right number, row by row, until the left reaches 1.
- 35 | 859
- 17 | 1,718
- 8 | 3,436
- 4 | 6,872
- 2 | 13,744
- 1 | 27,488
Step 3Cross out every row with an even number on the left.
- Cross out 8 | 3,436
- Cross out 4 | 6,872
- Cross out 2 | 13,744
Step 4Add the right column of the rows that are left: 859 + 1,718 + 27,488 = 30,065.
Step 5So 859 × 35 = 30,065.

Step 1 of 5

What this worksheet covers

Set A of this grade 5 missing number sheet holds 24 multiplication problems on one printable page, with the answer key on the page behind it. What makes this set particular: the blank moves between positions from problem to problem, so no single procedure clears the page and the numbers run as high as 44,676. Two problems from the middle of the page — "152 × ___ = 10032" and "147 × ___ = 8673" — show the range. The sheet sits inside Common Core 5.NBT.5, in the grade 5 Number & Operations in Base Ten strand.

Skills practiced

The grade 5 multiplication sequence covers three-digit by two-digit multiplication and multiplying by powers of ten; this page sits inside it. The skill on the page: three-digit by two-digit multiplication. Concretely, the sheet tests whether a student can reason backwards from a result to a missing part.

About the missing number format

The 24 problems here move the unknown around, so a student solves for a missing part as often as for a result; problem 9, "152 × ___ = 10032" is one of them. An unknown factor is division in disguise, so this format is where multiplication and division fact families are built.

Set A, Set B and Set C

The three sets come from the same generator with three different seeds: same skill, same layout, fresh numbers, and an answer key computed with the problems. Where Set A's problem 13 is "472 × ___ = 42008", Set B's is "___ × 56 = 44072".

How to use this worksheet

By grade 5 a student should take all 24 multiplication problems in one sitting. If the page takes more than about fifteen minutes, the underlying facts are probably not automatic yet, and that is worth fixing before more multiplication practice piles on. Keep the key face down until all 24 problems are finished, then go through the misses together rather than only totaling the score.

One mistake to watch for

Zeros are lost when multiplying by multiples of ten: 6 × 40 is answered 24 instead of 240. Problem 16 on this grade 5 missing number page, "830 × 26 = ___", is where to look for it.

The fact 6 × 4 is recalled and the ten is forgotten.

Rewrite 6 × 40 as 6 × 4 × 10 for a few days so the ten is a visible factor rather than a decoration.

The full guide to teaching multiplicationTeaching multiplication from equal groups to integer exponents: the grade 2–8 progression, times-table strategies, and the errors that stall students.